document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=85978>Question 85978</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many sides does a polygon have if the sum of the measures of its interior angles is 6 times the sum of the measures of its exterior angles </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #66846 by </B><A HREF=/tutors/aboutme.mpl?userid=psychopsibilin><B>psychopsibilin(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=psychopsibilin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=66846\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> we know that for a 'n' sided polygon, the sum of interior angles is (2n-4)*90.. at the same time, we also know that the sum of exterior angles of a polygon is always 360 degrees. from the question we understand that:<BR>\n" );
document.write( "(2n-4)*90 = 6*360<BR>\n" );
document.write( "or 2n-4 = (6*360/9) = 24<BR>\n" );
document.write( "hence 2n=28<BR>\n" );
document.write( "hence n=14\r<BR>\n" );
document.write( "\n" );
document.write( "Therefore the polygon has 14 sides.  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );