document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1053209>Question 1053209</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A train was traveling at 15m/s and sped up to 30 m/s over a distance of 1600m. What was its acceleration? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #668448 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=668448\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A train was traveling at 15m/s and sped up to 30 m/s over a distance of 1600m. What was its acceleration?<BR>\n" );
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document.write( "Average speed for 1600 meters was (15+30)/2 = 22.5 m/sec<BR>\n" );
document.write( "Time to move 1600 m at 22.5 m/sec = 1600/22.5 = 640/9 seconds<BR>\n" );
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document.write( "Accel = (30-15)/(640/9) = 27/128 m/sec/sec<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "s = vt + at^2/2<BR>\n" );
document.write( "= 15*(640/9) + (27/256)*(640/9)^2<BR>\n" );
document.write( "= 3200/3 + 1600/3<BR>\n" );
document.write( "= 1600 meters </SPAN>\n" );
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