document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1053091>Question 1053091</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The mean amount purchased by a typical customer at Churchill's Grocery Store is $26.00 with a standard deviation of $6.00. Assume the distribution of amounts purchased follows the normal distribution. For a sample of 62 customers, answer the following questions.<BR>\n" );
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document.write( "a.	<BR>\n" );
document.write( "What is the likelihood the sample mean is at least $27.00? (Round z value to 2 decimal places and final answer to 4 decimal places.)<BR>\n" );
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document.write( "  Probability	<BR>\n" );
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document.write( "b.	<BR>\n" );
document.write( "What is the likelihood the sample mean is greater than $25.00 but less than $27.00? (Round z value to 2 decimal places and final answer to 4 decimal places.)<BR>\n" );
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document.write( "  Probability	 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #668446 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=668446\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> $26.00 with a standard deviation of $6.00<BR>\n" );
document.write( "TI syntax is normalcdf(smaller, larger, µ, &#963;).<BR>\n" );
document.write( "P(x >= 27) = normalcdf(27, 100, 26, 6)  100 a placeholder<BR>\n" );
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document.write( "P(25 &#8804; x &#8804; 27) =  normalcdf(25, 27, 26, 6) </SPAN>\n" );
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