document.write( "Question 92001: Lead shielding is used to contain radiation. The percent of a certain radiation that can penetrate x millimeters of lead shielding is given by r(x) = 100e^-1.5x. What percent of radiation, to the nearest tenth of a percent, will penetrate a lead shield that is 3 millimeters thick? \n" ); document.write( "
Algebra.Com's Answer #66835 by stanbon(75887)\"\" \"About 
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The percent of a certain radiation that can penetrate x millimeters of lead shielding is given by r(x) = 100e^-1.5x. What percent of radiation, to the nearest tenth of a percent, will penetrate a lead shield that is 3 millimeters thick?
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\n" ); document.write( "Let x = 3 and solve for r:
\n" ); document.write( "r(3) = 100e^(-1.5*3)
\n" ); document.write( "r(3) = 100e^(-4.5)
\n" ); document.write( "r(3) = 100*0.011089965
\n" ); document.write( "r(3) = 11.09 %
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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