document.write( "Question 1053056: in a single throw of two fair dice,find the probability that the production of the product of the numbers on the dice
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Algebra.Com's Answer #668347 by Edwin McCravy(20067) $\"\"$ $\"About$

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in a single throw of two fair dice,find the probability
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document.write( "The word \"between\" is ambiguous.\r\n" );
document.write( "Here are the rolls between 8 to 16, inclusive of products of\r\n" );
document.write( "8 and 16.\r\n" );
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document.write( "1.  (2,4) -> 2×4 = 8\r\n" );
document.write( "2.  (2,5) -> 2×5 = 10\r\n" );
document.write( "3.  (2,6) -> 2×6 = 12\r\n" );
document.write( "4.  (3,3) -> 3×3 = 9\r\n" );
document.write( "5.  (3,4) -> 3×4 = 12\r\n" );
document.write( "6.  (3,5) -> 3×5 = 15\r\n" );
document.write( "7.  (4,2) -> 4×2 = 8\r\n" );
document.write( "8.  (4,3) -> 4×3 = 12\r\n" );
document.write( "9.  (4,4) -> 4×4 = 16\r\n" );
document.write( "10.  (5,2) -> 5×2 = 10\r\n" );
document.write( "11.  (5,3) -> 5×3 = 15\r\n" );
document.write( "12.  (6,2) -> 6×2 = 12\r\n" );
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document.write( "There are 36 possible rolls.  \r\n" );
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document.write( "(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)\r\n" );
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document.write( "(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)\r\n" );
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document.write( "(3,1) (3,2) (3,3) (3,4) (3,5) (3,6) \r\n" );
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document.write( "(4,1) (4,2) (4,3) (4,4) (4,5) (4,6) \r\n" );
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document.write( "(5,1) (5,2) (5,3) (5,4) (5,5) (5,6) \r\n" );
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document.write( "(6,1) (6,2) (6,3) (6,4) (6,5) (6,6) \r\n" );
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document.write( "So the probability is 12 out of 36,\r\n" );
document.write( "or 12/36 which reduces to 1/3, if \"between\" is inclusive.\r\n" );
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document.write( "But if \"between\" means STRICTLY between, then it does \r\n" );
document.write( "not include products of 8 or 16, and the possible rolls \r\n" );
document.write( "would be:\r\n" );
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document.write( "1.  (2,5) -> 2×5 = 10\r\n" );
document.write( "2.  (2,6) -> 2×6 = 12\r\n" );
document.write( "3.  (3,3) -> 3×3 = 9\r\n" );
document.write( "4.  (3,4) -> 3×4 = 12\r\n" );
document.write( "5.  (3,5) -> 3×5 = 15\r\n" );
document.write( "6.  (4,3) -> 4×3 = 12\r\n" );
document.write( "7.  (5,2) -> 5×2 = 10\r\n" );
document.write( "8.  (5,3) -> 5×3 = 15\r\n" );
document.write( "9.  (6,2) -> 6×2 = 12\r\n" );
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document.write( "If this is the case, then the probability is 9 out of 36,\r\n" );
document.write( "or 9/36 which reduces to 1/4, if \"between\" leaves out 8\r\n" );
document.write( "and 16.\r\n" );
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document.write( "So you'll have to decide which of those two answers is\r\n" );
document.write( "the one you're looking for.  You might ask your teacher.\r\n" );
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\n" ); document.write( "(2) divisible by 4.
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document.write( "1.  (1,4) -> 1×4 = 4\r\n" );
document.write( "2.  (2,2) -> 2×2 = 4\r\n" );
document.write( "3.  (2,4) -> 2×4 = 8\r\n" );
document.write( "4.  (2,6) -> 2×6 = 12\r\n" );
document.write( "5.  (3,4) -> 3×4 = 12\r\n" );
document.write( "6.  (4,1) -> 4×1 = 4\r\n" );
document.write( "7.  (4,2) -> 4×2 = 8\r\n" );
document.write( "8.  (4,3) -> 4×3 = 12\r\n" );
document.write( "9.  (4,4) -> 4×4 = 16\r\n" );
document.write( "10.  (4,5) -> 4×5 = 20\r\n" );
document.write( "11.  (4,6) -> 4×6 = 24\r\n" );
document.write( "12.  (5,4) -> 5×4 = 20\r\n" );
document.write( "13.  (6,2) -> 6×2 = 12\r\n" );
document.write( "14.  (6,4) -> 6×4 = 24\r\n" );
document.write( "15.  (6,6) -> 6×6 = 36\r\n" );
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document.write( "The probability is 15 out of 36, or 15/36 which \r\n" );
document.write( "reduces to 5/12.\r\n" );
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document.write( "Edwin

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