document.write( "Question 1053022: I have to write the complex expression in rectangular standard form: (square root -3 + i)^6
\n" ); document.write( "Any idea how you write it in standard form?
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Algebra.Com's Answer #668311 by KMST(5328)\"\" \"About 
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\"%28sqrt%28-3%29+%2Bi%29%5E6\" ? \"%28sqrt%283%29%2Bi%29%5E6\" ?
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\n" ); document.write( "\"%28sqrt%283%29%2Bi%29%5E6\" has more charm as a problem,
\n" ); document.write( "because \"sqrt%283%29%2Bi\" has a real part, \"sqrt%283%29\" and an imaginary part \"1%2Ai\" ,
\n" ); document.write( "so it begs for using the polar form.
\n" ); document.write( "\"r=sqrt%28%28sqrt%283%29%29%5E2%2B1%5E2%29=sqrt%283%2B1%29=sqrt%284%29=2\"
\n" ); document.write( "\"tan%28theta%29=1%2Fsqrt%283%29=sqrt%283%29%2F3\" , so \"system+%28theta=pi%2F6%2C%22or%22%2Ctheta=pi%2Bpi%2F6%29\" ,
\n" ); document.write( "but since \"sqrt%283%29%3E0\" and \"1%3E0\" , it must be \"theta+=pi%2F6\" , in the first quadrant.
\n" ); document.write( "So, \"sqrt%283%29%2Bi=2%28cos%28pi%2F6%29%2Bi%2Asin%28pi%2F6%29%29\" and
\n" ); document.write( "\"%28sqrt%283%29%2Bi%29%5E6=2%5E6%28cos%28pi%29%2Bi%2Asin%28pi%29%29=64%28-1%2Bi%2A0%29=-64\" .
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\n" ); document.write( " is a real number,
\n" ); document.write( "but from then on it gets complicated.
\n" ); document.write( "=\"-%284%2B2sqrt%283%29%29%5E3\"
\n" ); document.write( "= \n" ); document.write( "
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