document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1052846>Question 1052846</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm stuck on this and would really like some help!\r<BR>\n" );
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document.write( "Consider selecting one card at a time from a 52-card deck. What is the probability that the first card is an ace and the second card is also an ace? (Note: There are 4 aces in a deck of cards)\r<BR>\n" );
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document.write( "Please show all work!\r<BR>\n" );
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document.write( "(a) Assuming the card selection is without replacement.<BR>\n" );
document.write( "(b) Assuming the card selection is with replacement.\r<BR>\n" );
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document.write( "Thank you so much for your help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #668217 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=668217\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> With no replacement, the probability of drawing two aces in a row are 4/52 x 3/51:<BR>\n" );
document.write( "4/52 x 3/51=1/13 x 1/17=1/221, or 0.0045248<BR>\n" );
document.write( "With replacement, the probability is 1/13 x 1/13, which equals 1/169, or 0.0059171. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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