document.write( "Question 91997: Can someone check my work. You can't imagine how grateful I am to this site and to all of the tutors. I am able to see step by step my mistakes. thank you.\r
\n" ); document.write( "\n" ); document.write( "state the domain...I think I have it...maybe
\n" ); document.write( "f(x) = sq rt x+4
\n" ); document.write( " x + 4 = 0 - 4
\n" ); document.write( " x = -4 is the domain???\r
\n" ); document.write( "\n" ); document.write( "g(x) = 2x+1/x-3
\n" ); document.write( " x-3= 0
\n" ); document.write( " x - 3 = 0 + 3
\n" ); document.write( " x = 3\r
\n" ); document.write( "\n" ); document.write( "h(x)= 3x^2 + 5x - 3
\n" ); document.write( " all of the numbers are real, correct?
\n" ); document.write( " or
\n" ); document.write( " 9x + 5x -3
\n" ); document.write( " 14x-3 = 0
\n" ); document.write( " that's not right\r
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\n" ); document.write( "\n" ); document.write( "l(x) = 2x + 3
\n" ); document.write( " D = all real numbers\r
\n" ); document.write( "\n" ); document.write( "m(x) = 3/x^2 + 7
\n" ); document.write( " x + 7 = 0
\n" ); document.write( " x + 7 = 0 - 7
\n" ); document.write( " x = -7
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Algebra.Com's Answer #66819 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"f%28x%29+=+sqrt%28x%2B4%29\"\r
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\n" ); document.write( "\n" ); document.write( "Set the radicand (everything in the square root) greater than zero (remember you cannot take the square root of a negative number)\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B4%3E0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%3E-4\" Subtract 4 from both sides\r
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\n" ); document.write( "\n" ); document.write( "So the domain is x can be any number greater than -4\r
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\n" ); document.write( "\n" ); document.write( "\"g%28x%29+=+%282x%2B1%29%2F%28x-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x-3=0\" Set the denominator equal to zero\r
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\n" ); document.write( "\n" ); document.write( "\"x=3\" Add 3 to both sides. So x=3 is excluded from the domain since it makes the denominator equal to zero\r
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\n" ); document.write( "\n" ); document.write( "So x can be any number except 3\r
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\n" ); document.write( "\n" ); document.write( "\"h%28x%29=+3x%5E2+%2B+5x+-+3\"\r
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\n" ); document.write( "\n" ); document.write( "you are correct, x can be any real number\r
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\r
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\n" ); document.write( "\n" ); document.write( "l(x) = 2x + 3\r
\n" ); document.write( "\n" ); document.write( "you are correct, x can be any real number\r
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\n" ); document.write( "\n" ); document.write( "\"m%28x%29+=+3%2F%28x%5E2+%2B+7%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2B+7=0\" Set the denominator equal to zero\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=-7\" Subtract 7 from both sides\r
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\n" ); document.write( "\n" ); document.write( "Since you cannot take the square root of a negative and get a real answer, there are no values of x that will make \"x%5E2+%2B+7\" equal zero. So the domain is x is an element of all real numbers
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