document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1052839>Question 1052839</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x^3-x^2-x-2>0 solve inequality </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #668170 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=668170\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if you use synthetic division and use the possible values of x to be equal to plus or minus 1 or 2, you will find that the graph crosses the x-axis at x = 2\r<BR>\n" );
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document.write( "the equation becomes (x-2) * (x^2 + x + 1) = 0\r<BR>\n" );
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document.write( "if you try to factor x^2 + x + 1, you will find that the roots are complex.\r<BR>\n" );
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document.write( "this should mean that the graph only crosses the x-axis at x = 2.\r<BR>\n" );
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document.write( "when x < 2, the graph is negative.\r<BR>\n" );
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document.write( "when x > 2, the graph is positive.\r<BR>\n" );
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document.write( "the solution should be that the equation is > 0 when x > 2.\r<BR>\n" );
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document.write( "here's the graph of the equation.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" src = \"http://theo.x10hosting.com/2016/101406.jpg\" alt=\"$$$\" </>\r<BR>\n" );
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document.write( "the concept involved is as follows:\r<BR>\n" );
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document.write( "let a = (x-2)\r<BR>\n" );
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document.write( "let b = (x^2 + x + 1)\r<BR>\n" );
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document.write( "a * b = 0 if a = 0 or if b = 0 or if a and b are both equal to 0.\r<BR>\n" );
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document.write( "a = (x-2) = 0 when x = 2\r<BR>\n" );
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document.write( "b = (x^2 + x + 1) is never equal to 0, because the value of x when b = 0 is not real.\r<BR>\n" );
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document.write( "in other words, the graph of x^2 + x + 1 never crosses the x-axis because its roots are not real.\r<BR>\n" );
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document.write( "therefore, the only possibility for a * b = 0 is when a = 0 which is when (x-2) is equal to 0 which occurs when x = 2.\r<BR>\n" );
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document.write( "the graph confirms the logic.\r<BR>\n" );
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document.write( "the logic appears to be sound.\r<BR>\n" );
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document.write( "i did a couple of tests to see if this was true and it appears that it is.\r<BR>\n" );
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document.write( "either way, your solution is that the equation is > 0 when x > 2.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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