document.write( "Question 1052870: Find the equation of the line that contains the point \r
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document.write( "P(2, 3)
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document.write( " and is perpendicular to the graph of \r
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document.write( "y =3/2x-1 \n" );
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Algebra.Com's Answer #668160 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Two lines that are perpendicular have a slope product that is the negative reciprocal, or -1. \n" ); document.write( "y=(3/2)x-1 has a slope of 3/2 \n" ); document.write( "To find the negative reciprocal, flip the fraction and change the sign. The negative reciprocal is -2/3 \n" ); document.write( "Now use the point slope formula where \n" ); document.write( "y-y1=m(x-x1), where (x1,y1) is the point and m the slope \n" ); document.write( "y-3=(-2/3)(x-2) \n" ); document.write( "y-3=-(2/3)x+(4/3) \n" ); document.write( "3 is 9/3 \n" ); document.write( "y=-(2/3)x+13/3 ANSWER \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |