document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1052869>Question 1052869</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the line that contains the point P(&#8722;2, 0)<BR>\n" );
document.write( " and is perpendicular to the graph of y=2/3x-3\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #668157 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=668157\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the line that contains the point P(-2,0)<BR>\n" );
document.write( " and is perpendicular to the graph of y=2/3x-3<BR>\n" );
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document.write( "The slope of y = (2/3)x-3 is 2/3<BR>\n" );
document.write( "The slope of lines perpendicular is the negative inverse, -3/2<BR>\n" );
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document.write( "Use <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+-+y%5B1%5D+=+m%2A%28x+-+x%5B1%5D%29 ALIGN=MIDDLE  ALT=\"y+-+y%5B1%5D+=+m%2A%28x+-+x%5B1%5D%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > where (x1,y1) is the point.\r<BR>\n" );
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document.write( "y-0 = (-3/2)*(x+2)<BR>\n" );
document.write( "y = (-3/2)*(x+2)\r<BR>\n" );
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