document.write( "Question 1052857: Can you please help with this?\r
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document.write( "An insurance company checks police records on 600 randomly selected auto accidents and notes that teenagers were at the wheel in 90 of them. Construct a 95% confidence interval estimate of the proportion of auto accidents that involve teenage drivers.\r
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document.write( "Thank you very much for any help! \n" );
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Algebra.Com's Answer #668151 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! The point estimate is 90/600=0.15 \n" ); document.write( "The standard error is sqrt(p*(1-p))/n) \n" ); document.write( "sqrt(0.15*-0.85)/600 \n" ); document.write( "=sqrt(0.0002125) \n" ); document.write( "=0.0146 \n" ); document.write( "95% CI is p hat +/- 1.96*SE \n" ); document.write( "the interval is +/-0.0286 \n" ); document.write( "The 95%CI for the true proportion is (0.121,0.179) \n" ); document.write( " |