document.write( "Question 1052832: a mother is 5 times older than her daughter, 5 years ago the sum of their ages was 50, find their present ages?
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Algebra.Com's Answer #668140 by Alan3354(69443)\"\" \"About 
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a mother is 5 times older than her daughter, 5 years ago the sum of their ages was 50, find their present ages?
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\n" ); document.write( "a mother is 5 times older than her daughter
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\n" ); document.write( "1 time older = 2 times as old
\n" ); document.write( "2 times older = 3 times as old
\n" ); document.write( "3 times older = 4 times as old
\n" ); document.write( "4 times older = 5 times as old
\n" ); document.write( "5 times older = 6 times as old
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\n" ); document.write( "M = 6D
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\n" ); document.write( "5 years ago the sum of their ages was 50 --> the is now 60
\n" ); document.write( "M + D = 60
\n" ); document.write( "S for M
\n" ); document.write( "6D + D = 60
\n" ); document.write( "D = 60/7 years
\n" ); document.write( "M = 360/7 years\r
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