document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1052799>Question 1052799</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The equation c=1.2 x plus 85.73 can be used to estimate the cost c of a holiday dinner for 10 people x years after 2000. Determine in what year the cost of a dinner for 10 people will be &#8203;$95.33. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #668133 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=668133\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The equation c=1.2 x plus 85.73 can be used to estimate the cost c of a holiday dinner for 10 people x years after 2000. Determine in what year the cost of a dinner for 10 people will be &#8203;$95.33. <BR>\n" );
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document.write( "C(x) = 1.2x + 85.73<BR>\n" );
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document.write( "Solve::<BR>\n" );
document.write( "95.33 = 1.2x + 85.73<BR>\n" );
document.write( "1.2x = 9.6<BR>\n" );
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document.write( "x = 8 years<BR>\n" );
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document.write( "Ans: 2000 + 8 = 2008<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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