document.write( "Question 91965: Solve the following systems by addition. If a unique solution does not exist, state whether the system is inconsistent or dependent.\r
\n" ); document.write( "\n" ); document.write( "x + 5y = 10
\n" ); document.write( "2x - 10y=20
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Algebra.Com's Answer #66812 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"1%2Ax%2B5%2Ay=10\"
\n" ); document.write( " \"2%2Ax-10%2Ay=20\"
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\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
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\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
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\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 1 and 2 to some equal number, we could try to get them to the LCM.
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\n" ); document.write( " Since the LCM of 1 and 2 is 2, we need to multiply both sides of the top equation by 2 and multiply both sides of the bottom equation by -1 like this:
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\n" ); document.write( " \"2%2A%281%2Ax%2B5%2Ay%29=%2810%29%2A2\" Multiply the top equation (both sides) by 2
\n" ); document.write( " \"-1%2A%282%2Ax-10%2Ay%29=%2820%29%2A-1\" Multiply the bottom equation (both sides) by -1
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\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"2%2Ax%2B10%2Ay=20\"
\n" ); document.write( " \"-2%2Ax%2B10%2Ay=-20\"
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\n" ); document.write( " Notice how 2 and -2 add to zero (ie \"2%2B-2=0\")
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\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%282%2Ax-2%2Ax%29%2B%2810%2Ay%2B10%2Ay%29=20-20\"
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\n" ); document.write( " \"%282-2%29%2Ax%2B%2810%2B10%29y=20-20\"
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\n" ); document.write( " \"cross%282%2B-2%29%2Ax%2B%2810%2B10%29%2Ay=20-20\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
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\n" ); document.write( " So after adding and canceling out the x terms we're left with:
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\n" ); document.write( " \"20%2Ay=0\"
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\n" ); document.write( " \"y=0%2F20\" Divide both sides by \"20\" to solve for y
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\n" ); document.write( " \"y=0\" Reduce
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\n" ); document.write( " Now plug this answer into the top equation \"1%2Ax%2B5%2Ay=10\" to solve for x
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\n" ); document.write( " \"1%2Ax%2B5%280%29=10\" Plug in \"y=0\"
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\n" ); document.write( " \"1%2Ax%2B0=10\" Multiply
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\n" ); document.write( " \"1%2Ax=10-0\" Subtract \"0\" from both sides
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\n" ); document.write( " \"1%2Ax=10\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F1%29%281%29%29%2Ax=%2810%29%281%2F1%29\" Multiply both sides by \"1%2F1\". This will cancel out \"1\" on the left side.
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\n" ); document.write( " \"x=10\" Multiply the terms on the right side
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\n" ); document.write( " So our answer is
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\n" ); document.write( " \"x=10\", \"y=0\"
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\n" ); document.write( " which also looks like
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\n" ); document.write( " (\"10\", \"0\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"1%2Ax%2B5%2Ay=10\"
\n" ); document.write( " \"2%2Ax-10%2Ay=20\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"1%2Ax%2B5%2Ay=10\" (red) \"2%2Ax-10%2Ay=20\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
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\n" ); document.write( " and we can see that the two equations intersect at (\"10\",\"0\"). This verifies our answer.
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