document.write( "Question 1052802: If x=log10^12,y=log4^2Ślog10^9 and z=log10^0.4 find x-y-z \n" ); document.write( "
Algebra.Com's Answer #668107 by Edwin McCravy(20059)\"\" \"About 
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document.write( "log(A) means the power to which 10 must be raised to give A.\r\n" );
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document.write( "log10^12 = 12 because the power to which 10 must be raised\r\n" );
document.write( "in order to get 10 raised to the 12th power is 12.\r\n" );
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document.write( "log10^9 = 9 because the power to which 10 must be raised\r\n" );
document.write( "in order to get 10 raised to the 9th power is 9.\r\n" );
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document.write( "log10^0.4 = 0.4 because the power to which 10 must be raised\r\n" );
document.write( "in order to get 10 raised to the 0.4th power is 0.4.\r\n" );
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document.write( "[The above requires the same reasoning as \r\n" );
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document.write( "\"The city to which you must be in -- \r\n" );
document.write( "in order to be in Chicago -- is Chicago.\"  :)]\r\n" );
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document.write( "So\r\n" );
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document.write( "If x=log10^12,y=log4^2Ślog10^9 and z=log10^0.4 find x-y-z\r\n" );
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document.write( "becomes:\r\n" );
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document.write( "If x=12,y=log4^2Ś9 and z=0.4 find x-y-z\r\n" );
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document.write( "So x-y-z = 12-9Ślog4^2-0.4 = 11.6-9Ślog4^2 = ll.6-9Ślog16 = \r\n" );
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document.write( "11.6-9Ś1.204119983 = 0.762920153.\r\n" );
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document.write( "Edwin
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