document.write( "Question 1052727: mr. meyers is creating a seating chart for his class. There are 12 desks for 9 students. If he creates a different seating chart for every day, how many days will pass until he has to repeat a seating chart? \n" ); document.write( "
Algebra.Com's Answer #668091 by KMST(5328)\"\" \"About 
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He can assign
\n" ); document.write( "Adam to any of the \"12\" desks.
\n" ); document.write( "In each of those cases, th first choice leaves \"12-1=11\" choices of seat for Bob.
\n" ); document.write( "For each of the \"12%2A11\" resulting cases, there would be \"10\" choices for the seat assigned to Carl.
\n" ); document.write( "For each of the \"12%2A11%2A10\" sets of seats assigned to Adam, Bob, and Carl, there would be \"9\" possible places to sit Daniel.
\n" ); document.write( "So far we have \"12%2A11%2A10%2A9\" ways to sit the first 4 students,
\n" ); document.write( "and Mr Meyers still has to choose seats for Ed, Frank, George, Harry, and Ian.
\n" ); document.write( "All in all, he has \"12%2A11%2A10%2A9%2A8%2A7%2A6%2A5%2A4=79833600\" possible seating arrangements.
\n" ); document.write( "To go through all 79.8336 million possible seating charts would take him that many days. assuming the class meets for 365 days per year, that would be over 200 thousand years. I do not believe Mr Meyers can live that long.
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