document.write( "Question 1052741: A train leaves San Diego at 1:00 PM. A second train leaves the same city in the same direction at 3:00 PM. The second train travels 30 mph faster than the first. If the second train overtakes the first at 6:00 PM, what is the speed of each of the two trains? \n" ); document.write( "

Algebra.Com's Answer #668079 by josgarithmetic(39617) $\"\"$ $\"About$

You can put this solution on YOUR website!
A very typical catchup-travel type problem. Basic constant travel rate rule is RT=D. Time is best handled in quantities, and not as points on a time-line, but this is only to make handling easier values for analyzing and solving the problem.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Only a data table is presented here. You do the rest.\r
\n" ); document.write( "\n" ); document.write( "

\r\n" );
document.write( "                  SPEEDS           TIME           DISTANCE\r\n" );
document.write( "FIRST             r                t+2             d\r\n" );
document.write( "SECOND            r+30              t              d\r\n" );
document.write( "

\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Excuse me. I left something out.
\n" ); document.write( " $\"highlight_green%28t%2B2=5%29\"$ .\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Here is an adjustment to the data table, using according to the meaning of the time points in the description:
\n" ); document.write( "

\r\n" );
document.write( "                  SPEEDS           TIME           DISTANCE\r\n" );
document.write( "FIRST             r                 5              d\r\n" );
document.write( "SECOND            r+30              3              d\r\n" );
document.write( "

\r
\n" ); document.write( "\n" ); document.write( "NOW you can do the rest.
\n" ); document.write( " \n" ); document.write( "

\n" );