document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1052726>Question 1052726</A>: <I><SPAN STYLE=\"word-break: break-all;\"> for the curve -36+39x-3x^3, state the nature of the stationery points and location of the points?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #668063 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=668063\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -36+39x-3x^3=f(x)\r<BR>\n" );
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document.write( "the derivative is -9x^2+39<BR>\n" );
document.write( "Set it equal to 0 and solve<BR>\n" );
document.write( "9x^2=39<BR>\n" );
document.write( "x^2=39/9<BR>\n" );
document.write( "x=+/-sqrt(39)/3<BR>\n" );
document.write( "Numerically, this is +/-2.082<BR>\n" );
document.write( "Graphically, the y value is -90.12 at x=-2.08 and 18.12 and x=+2.08<BR>\n" );
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