document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1052703>Question 1052703</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help finding the polynomial with the given zeros of 0, 8, and 1+sqrt2i with real coefficients please! I've tried and so far all I've gotten is x^2-8x-x+sqrt2i+8+sqrt2i\r<BR>\n" );
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document.write( "Any help is appreciated, thanks!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #668038 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=668038\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> with zeros of 0 and 8, the factors are x and (x-8)<BR>\n" );
document.write( "1+/-sqrt2i needs to be found.<BR>\n" );
document.write( "[-b +/- sqrt (b^2-4ac)](1/2) needs to be evaluated<BR>\n" );
document.write( "if a is 1 and b is -2, x=(1/2)(2 +/- sqrt (4-4(1)(c))<BR>\n" );
document.write( "This gives me 1 +/- sqrt (4-4c), and that has to become negative 16, because then it will be 4i, and it is divided by 2 in the formula, and that will be 2i.<BR>\n" );
document.write( "c has to be 5, then sqrt (4-4c)=sqrt(-16)<BR>\n" );
document.write( "The third factor is (x^2-2x+5), and x=(1/2)+/- (2 +/- sqrt (4-20))<BR>\n" );
document.write( "=(1/2)(2+/-4i)=1+/-2i\r<BR>\n" );
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document.write( "The polynomial is x(x-8)(x^2-2x+5)=x^4-10x^3+21x^2-40x.<BR>\n" );
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