document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1052697>Question 1052697</A>: <I><SPAN STYLE=\"word-break: break-all;\"> . Joey has 57 coins in his pocket—all nickels and dimes. He counted the change and came  to a total of $4.35. How many each coin does he have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #668021 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=668021\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n be nickels, and d be dimes. Then you have two equations:<BR>\n" );
document.write( "n+d=57<BR>\n" );
document.write( "5n+10d=435<BR>\n" );
document.write( "So:<BR>\n" );
document.write( "5n+5d=285<BR>\n" );
document.write( "5n+10d=435<BR>\n" );
document.write( "5d=150<BR>\n" );
document.write( "d=30<BR>\n" );
document.write( "n=27<BR>\n" );
document.write( "Joey has 30 dimes, and 27 nickels. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );