document.write( "Question 1052638: a three person maintenance crew could clean a certain building in 4h, whereas a four person crew could do the job in 3h. if one worker of the four person crew was an hour late, how long did the job take?
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Algebra.Com's Answer #667975 by Fombitz(32388) $\"\"$ $\"About$

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Rate*Time=Output
\n" ); document.write( "Say an output of 100 makes the job complete.
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\n" ); document.write( "For a 3 person crew,
\n" ); document.write( " $\"R%5B3%5D%2A4=100\"$
\n" ); document.write( " $\"R%5B3%5D=100%2F4\"$
\n" ); document.write( " $\"R%5B3%5D=25\"$
\n" ); document.write( "For a 4 person crew,
\n" ); document.write( " $\"R%5B4%5D%2A3=100\"$
\n" ); document.write( " $\"R%5B4%5D=100%2F3\"$ \r
\n" ); document.write( "\n" ); document.write( "So for the first hour, it was only a 3 person crew.
\n" ); document.write( " $\"25%2A1=25\"$
\n" ); document.write( "So they completed 25 units of output which leaves 75 units to complete.
\n" ); document.write( "Now switch to the 4 person rate,
\n" ); document.write( " $\"%28100%2F3%29t=75\"$
\n" ); document.write( " $\"t=%2875%2A3%29%2F100\"$
\n" ); document.write( " $\"t=9%2F4\"$ $\"hr\"$
\n" ); document.write( "So adding the hour from before,
\n" ); document.write( " $\"t%5BTOT%5D=1%2B9%2F4\"$
\n" ); document.write( " $\"t%5BTOT%5D=13%2F4\"$
\n" ); document.write( " $\"t%5BTOT%5D=3%261%2F4\"$ $\"hr\"$
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