document.write( "Question 1052603: The perimeter of a bulletin board is 136. The length is represented as 2 more than 2 times the width. The width is represented as w. What are the dimensions of the bulletin board? \n" ); document.write( "

Algebra.Com's Answer #667958 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
I'm assuming the bulletin board is a rectangle.
\n" ); document.write( " $\"P=2L%2B2W\"$
\n" ); document.write( " $\"2L%2B2W=136\"$
\n" ); document.write( " $\"L%2BW=68\"$
\n" ); document.write( "and
\n" ); document.write( " $\"L=2%2B2W\"$
\n" ); document.write( "Substituting,
\n" ); document.write( " $\"2%2B2W%2BW=68\"$
\n" ); document.write( " $\"3W=66\"$
\n" ); document.write( " $\"W=22\"$
\n" ); document.write( "So then,
\n" ); document.write( " $\"L%2B22=68\"$
\n" ); document.write( " $\"L=46\"$
\n" ); document.write( " \n" ); document.write( "

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