document.write( "Question 91968: How can I show the equation use for the solution?
\n" ); document.write( "A coffee merchant has coffee beans that sell for $9 per
\n" ); document.write( "pound and $12 per pound. The two types are to be mixed to create 100 lb of a mixture that will sell for $11.25 per pound. How much of each type of bean should be used in the mixture?
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Algebra.Com's Answer #66793 by mathispowerful(115)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "The idea is that the total worth of coffee will remain unchanged before and after mixture.\r
\n" ); document.write( "\n" ); document.write( "Let x represent the amount of $9-coffee
\n" ); document.write( " y represent the amount of $12-coffee\r
\n" ); document.write( "\n" ); document.write( "then
\n" ); document.write( " x + y = 100
\n" ); document.write( " 9x + 12y = 11.25 * 100 = 1125\r
\n" ); document.write( "\n" ); document.write( "so we have \r
\n" ); document.write( "\n" ); document.write( "x + y = 100
\n" ); document.write( "9x + 12y = 1125\r
\n" ); document.write( "\n" ); document.write( "multiply -9 on both sides of first equation
\n" ); document.write( "-9x - 9y = -900\r
\n" ); document.write( "\n" ); document.write( "add to second equation\r
\n" ); document.write( "\n" ); document.write( "3y = 225\r
\n" ); document.write( "\n" ); document.write( "y = 75 lbs
\n" ); document.write( "and x = 100 -75 = 25 lbs\r
\n" ); document.write( "\n" ); document.write( "so we need to mix 25 lbs of $9-coffee with 75 lbs of $12-coffee.\r
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