document.write( "Question 1052526: Given \"+g%28x%29+=+%283x%5E2%2B4x-3%29%2F%28x%5E2%2B3%29+\" , determine the horizontal asymptote and the point where the graph crosses the horizontal asymptote \n" ); document.write( "
Algebra.Com's Answer #667906 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"%283x%5E2%2B4x-3%29%2F%28x%5E2%2B3%29=%283%2B4%2Fx-3%2Fx%5E2%29%2F%281%2B3%2Fx%5E2%29\"
\n" ); document.write( "In the limit as x goes to \"infinity\" and \"-infinity\",
\n" ); document.write( "\"g%28x%29=3\"
\n" ); document.write( "So the horizontal asymptote is \"y=3\".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "Crossing the horizontal asymptote,
\n" ); document.write( "\"%283x%5E2%2B4x-3%29%2F%28x%5E2%2B3%29=3\"
\n" ); document.write( "\"3x%5E2%2B4x-3=3x%5E2%2B9\"
\n" ); document.write( "\"4x=12\"
\n" ); document.write( "\"x=3\"
\n" ); document.write( "Then,
\n" ); document.write( "\"y=%283%283%29%5E2%2B4%283%29-3%29%2F%283%5E2%2B3%29=%2827%2B12-3%29%2F%289%2B3%29=36%2F12=3\"
\n" ); document.write( "(3,3)
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "
\n" );