document.write( "Question 1052529: In a container, there are dimes and nickels. There are 10 more nickels than dimes and the nickels and dimes add up to $3.50. How many nickels and dimes are there? \n" ); document.write( "
Algebra.Com's Answer #667868 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! In a container, there are dimes and nickels. There are 10 more nickels than dimes and the nickels and dimes add up to $3.50. How many nickels and dimes are there? \n" ); document.write( "----------- \n" ); document.write( "Here's one way: \n" ); document.write( "n = d + 10 \n" ); document.write( "5n + 10d = 350 \n" ); document.write( "==================== \n" ); document.write( "Here's another: \n" ); document.write( "Without the 10 more nickels, the total is $3.00. \n" ); document.write( "Each set of 1 dime & 1 nickel = 15 cents. \n" ); document.write( "300/15 = 20 sets \n" ); document.write( "--> 20 dimes & 30 nickels \n" ); document.write( " \n" ); document.write( " |