document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1052489>Question 1052489</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I tried much in this problem but I didn't get my answer correct.\r<BR>\n" );
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document.write( "The question is---\r<BR>\n" );
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document.write( "A person draws two cards successively without replacement from a pack of 52 playing cards.He tells that both cards are aces,then the probability that both cards are aces if there are 60% chances that he speaks truth-----<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #667843 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=667843\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the probability of drawing an ace out of the deck the first time is 4/52.\r<BR>\n" );
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document.write( "the probability of drawing an ace out of the deck the second time without replacement is 3/51.\r<BR>\n" );
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document.write( "the assumption is that you got the ace the first time and there are only 3 aces left out of 51 cards left.\r<BR>\n" );
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document.write( "so the probability of drawing two aces out of the deck without replacement is 4/52 * 3/51.\r<BR>\n" );
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document.write( "if the person speaks the truth 60% of the time, than he actually has two aces 60% of the time.\r<BR>\n" );
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document.write( "if the person lies 40% of the time, than he actually doesn't have two aces 40% of the time.\r<BR>\n" );
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document.write( "so, 60% of the time, the probability that he actually has two aces is 4/52 * 3/51, and 40% of the time, the probability that he actually has two aces is 0.\r<BR>\n" );
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document.write( "the overall probability that he actually has 2 aces is therefore .60 * 4/52 * 3/51 + .40 * 0 which is equal to .60 * 4/52 * 3/51 which is equal to .0027149321.\r<BR>\n" );
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document.write( "in fractional form, this is equal to 3/1105.\r<BR>\n" );
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document.write( "this is what i think is happening.\r<BR>\n" );
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document.write( "try it out and see if it's right.\r<BR>\n" );
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