document.write( "Question 1052455: You have already invested $300 in a stock with an annual return of 11%. How much of an additional $1,500 should be invested at 12% and how much at 6% so that the total return on the entire $1,800 is 9%? (Round each answer to the nearest cent.) \n" ); document.write( "

Algebra.Com's Answer #667817 by ikleyn(52796) $\"\"$ $\"About$

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\n" ); document.write( "You have already invested $300 in a stock with an annual return of 11%.
\n" ); document.write( "How much of an additional $1,500 should be invested at 12% and how much at 6% so that the total return on the entire $1,800 is 9%?
\n" ); document.write( "(Round each answer to the nearest cent.)
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document.write( "Let x = the amount invested at 12%,\r\n" );
document.write( "    y = the amount invested at  6%.\r\n" );
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document.write( "Then you have this system of two equations in two unknowns to find x and y.\r\n" );
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document.write( "    x +     y = 1500,                   (1)\r\n" );
document.write( "0.12x + 0.06y = 0.09*1800 - 0.11*300.   (2)\r\n" );
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document.write( "Solve it by any method you know.\r\n" );
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