document.write( "Question 1052460: Two hikers are 11 miles apart and walking toward each other. They meet in 2 hours. Find the rate of each hiker if one hiker walks 1.3 mph faster than the other. \n" ); document.write( "
Algebra.Com's Answer #667805 by rajagopalan(174)![]() ![]() You can put this solution on YOUR website! Let the Speed of the slow hiker =x \n" ); document.write( "Then Speed of fast hiker =x+1.3 \n" ); document.write( "Distance covered by them in 1 hr=2x+1.3 km \n" ); document.write( "Distance covered by them in 2 hrs=2(2x+1.3)=4x+2.6 km \n" ); document.write( "We have 4x+2.6=11 \n" ); document.write( "Then 4x=11-2.6 \n" ); document.write( "gives 4x=8.4 \n" ); document.write( "resulting in x=8.4/4=2.1 km \n" ); document.write( "Speed of slow hiker = 2.1 km ph \n" ); document.write( "Speed of fast hiker=3.4 km ph\r \n" ); document.write( "\n" ); document.write( "Verify: \n" ); document.write( "Distance covered by slow hiker in 2 hrs =4.2 \n" ); document.write( "Distance covered by fast hiker in 2 hrs =6.8 \n" ); document.write( "Summing upto.......................................=11.0 km \n" ); document.write( "Hence OK. \n" ); document.write( " |