document.write( "Question 1052460: Two hikers are 11 miles apart and walking toward each other. They meet in 2 hours. Find the rate of each hiker if one hiker walks 1.3 mph faster than the other. \n" ); document.write( "
Algebra.Com's Answer #667805 by rajagopalan(174)\"\" \"About 
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Let the Speed of the slow hiker =x
\n" ); document.write( "Then Speed of fast hiker =x+1.3
\n" ); document.write( "Distance covered by them in 1 hr=2x+1.3 km
\n" ); document.write( "Distance covered by them in 2 hrs=2(2x+1.3)=4x+2.6 km
\n" ); document.write( "We have 4x+2.6=11
\n" ); document.write( "Then 4x=11-2.6
\n" ); document.write( "gives 4x=8.4
\n" ); document.write( "resulting in x=8.4/4=2.1 km
\n" ); document.write( "Speed of slow hiker = 2.1 km ph
\n" ); document.write( "Speed of fast hiker=3.4 km ph\r
\n" ); document.write( "\n" ); document.write( "Verify:
\n" ); document.write( "Distance covered by slow hiker in 2 hrs =4.2
\n" ); document.write( "Distance covered by fast hiker in 2 hrs =6.8
\n" ); document.write( "Summing upto.......................................=11.0 km
\n" ); document.write( "Hence OK.
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