document.write( "Question 1052341: A radiator contains 10 quarts of fluid, 10% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 25% antifreeze? (Round your answer to two decimal places.) \n" ); document.write( "
Algebra.Com's Answer #667737 by jorel555(1290)\"\" \"About 
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Right now, you have 10 qts. of fluid, of which 10% is anti-freeze. Let n be the amount of pure anti-freeze to be added. Then:
\n" ); document.write( ".1(10)-.1n+n=.25(10)
\n" ); document.write( "1+.9n=2.5
\n" ); document.write( ".9n=1.5
\n" ); document.write( "n=1.67 qts. need to be replaced with pure anti-freeze to achieve the desired mix. ☺☺☺☺
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