document.write( "Question 1052216: Chuck and Dana agree to meet in Chicago over the weekend. Chuck travels 93 miles in the same time as Dana travels 84 miles if chucks rate of travels is 3mph more than Danas and they travel the same length of time at what speed does Chuck travel? \n" ); document.write( "
Algebra.Com's Answer #667647 by addingup(3677)\"\" \"About 
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distance = rate*time, for short: d = rt
\n" ); document.write( "Let r be Chuck's speed. Then, Dana's speed will be r-3
\n" ); document.write( "apply the formula to:
\n" ); document.write( "Chuck: 93 = rt
\n" ); document.write( "Dana: 84 = (r-3)t
\n" ); document.write( "Put it all together:
\n" ); document.write( "93/r = 84/(r-3)
\n" ); document.write( "Cross multiply:
\n" ); document.write( "93(r-3) = 84(r)
\n" ); document.write( "93r-93*3 = 84r
\n" ); document.write( "93r-84r = 93*3
\n" ); document.write( "9r = 279
\n" ); document.write( "r = 279/9
\n" ); document.write( "r = 31
\n" ); document.write( "Your answer:
\n" ); document.write( "Chuck: 93/31 = 3 so Chuck drives for 3 hours at 31mph
\n" ); document.write( "Dana: 31-3 = 28 so she drives for 3 hours at 28mph\r
\n" ); document.write( "\n" ); document.write( "Answer:
\n" ); document.write( "Chuck is driving at 42 mph (for 2 hours)
\n" ); document.write( "Dana is driving at 39 mph (for 2 hours) \n" ); document.write( "
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