document.write( "Question 1052084: George invested some money at 5% interest. George also invested $219 more than 4 times that amount at 10%. How much is invested at each rate if George receives $922.80 in interest after one year? \n" ); document.write( "
Algebra.Com's Answer #667587 by jorel555(1290)\"\" \"About 
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Let n be the amount of money invested at 5%. Then the 10% investment would be 4n+219. So:
\n" ); document.write( ".05n+.1(4n+219)=922.80
\n" ); document.write( ".45n+21.9=922.8
\n" ); document.write( ".45n=900.9
\n" ); document.write( "n=$2002 invested at 5%,$8227 invested at 10%. ☺☺☺☺
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