document.write( "Question 1052089: Systems of equations in three variables HELP!!
\n" );
document.write( "a+b=3
\n" );
document.write( "-b+c=3
\n" );
document.write( "a+2c=10 \n" );
document.write( "
Algebra.Com's Answer #667504 by ikleyn(52794)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "Systems of equations in three variables HELP!! \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "a + b = 3 (1)\r\n" ); document.write( " - b + c = 3 (2)\r\n" ); document.write( "a + 2c = 10 (3)\r\n" ); document.write( "\r\n" ); document.write( "Add equations (1) and (2) (both sides). You will get\r\n" ); document.write( "\r\n" ); document.write( "a + c = 6. (4)\r\n" ); document.write( "\r\n" ); document.write( "Distract equation (4) from the equation (3). You will get\r\n" ); document.write( "\r\n" ); document.write( "c = 10-6 = 4.\r\n" ); document.write( "\r\n" ); document.write( "So, you just found the solution for c: c=4.\r\n" ); document.write( "\r\n" ); document.write( "Substitute c=4 into equation (2). You will get\r\n" ); document.write( "\r\n" ); document.write( "-b + 4 = 3.\r\n" ); document.write( "\r\n" ); document.write( "Hence, b = 4-3 = 1.\r\n" ); document.write( "\r\n" ); document.write( "Substitute b=1 into equation (1). You will get\r\n" ); document.write( "\r\n" ); document.write( "a + 1 = 3.\r\n" ); document.write( "\r\n" ); document.write( "Hence, a = 3-1 = 2.\r\n" ); document.write( "\r\n" ); document.write( "Answer. a=2, b=1, c=4.\r\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |