document.write( "Question 1052074: A new printer can print a set of newsletters in 17 minutes less than an older printer can. If both printers work simultaneously, they can print the set of newsletters in 40 minutes. How long does it take the older printer alone to print the set of newsletters? \n" ); document.write( "

Algebra.Com's Answer #667485 by stanbon(75887) $\"\"$ $\"About$

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A new printer can print a set of newsletters in 17 minutes less than an older printer can. If both printers work simultaneously, they can print the set of newsletters in 40 minutes. How long does it take the older printer alone to print the set of newsletters?
\n" ); document.write( "New printer :: time = x-17 min/job ; rate = 1/(x-17) job/min
\n" ); document.write( "Old printer :: time = x min/job ; rate = 1/x job/min
\n" ); document.write( "Together :: time = 40 min/job ; rate = 1/40 job/min
\n" ); document.write( "-----
\n" ); document.write( "Equation:
\n" ); document.write( "rate + rate = rate
\n" ); document.write( "1/(x-17) + 1/x = 1/40
\n" ); document.write( "---------------------
\n" ); document.write( "40x + 40(x-17) = x(x-17)
\n" ); document.write( "80x - 680 = x^2 - 17x
\n" ); document.write( "x^2 - 97x + 680 = 0
\n" ); document.write( "x = 89.4 min (time for the the old printer to do the job)
\n" ); document.write( "--------------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "--------------------
\n" ); document.write( " \n" ); document.write( "

\n" );