document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=91847>Question 91847</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please can you help with this problem -3x is more than 0 and 3x-4 is less than 11 determine whether -4 satisfies each compound inequality   university of phoenix elementary and intermidiate algebra              <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #66741 by </B><A HREF=/tutors/aboutme.mpl?userid=mathispowerful><B>mathispowerful(115)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathispowerful><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=66741\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> replace x by -4 in each expression to see if it is true statement.\r<BR>\n" );
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document.write( "-3x :  -3(-4) = 12, since 12 > 0 , it is true;\r<BR>\n" );
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document.write( "3x - 4: 3(-4) - 4 = -16, since -16< 11, it is also true.\r<BR>\n" );
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document.write( "So -4 can satisfy both expressions. </SPAN>\n" );
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