document.write( "Question 1051961: A bicycle path is 6 miles long. A man walks from one end at the rate of 3 mph. At the same time, a friend bicycles from the other end, traveling at 15 mph. In how many minutes will they meet?
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #667392 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
You can think of this as one of them ( either one )
\n" ); document.write( "standing still and the other one approching at the
\n" ); document.write( "sum of their speeds
\n" ); document.write( "-------------------------------
\n" ); document.write( "Let \"+t+\" = time in hrs until they meet
\n" ); document.write( "\"+6+=+%28+3+%2B+15+%29%2At+\"
\n" ); document.write( "\"+6+=+18t+\"
\n" ); document.write( "\"+t+=+1%2F3+\" hrs
\n" ); document.write( "[ hrs ] x [ min/hr ] = [ min ]
\n" ); document.write( "\"+%281%2F3%29%2A%2860%2F1%29+=+20+\"
\n" ); document.write( "They will meet in 20 min
\n" ); document.write( "--------------------------
\n" ); document.write( "check answer:
\n" ); document.write( "\"+d%5B1%5D+=+3%2A%281%2F3%29+\"
\n" ); document.write( "\"+d%5B1%5D+=+1+\" mi
\n" ); document.write( "and
\n" ); document.write( "\"+d%5B2%5D+=+15%2A%281%2F3%29+\"
\n" ); document.write( "\"+d%5B2%5D+=+5+\" mi
\n" ); document.write( "-----------------------
\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+1+%2B+5+\"
\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+6+\" mi
\n" ); document.write( "OK
\n" ); document.write( "
\n" ); document.write( "
\n" );