document.write( "Question 1051958: use the change-of-base formula
\n" ); document.write( "to approximate the logarithm accurate to the nearest
\n" ); document.write( "ten-thousandth.\r
\n" ); document.write( "\n" ); document.write( "log7 20 \r
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\n" ); document.write( "\n" ); document.write( "log2 14\r
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Algebra.Com's Answer #667391 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
\"log%287%2C+%2820%29%29\"\"%22%22=%22%22\"\"log%28%2820%29%29%2Flog%28%287%29%29\"\"%22%22=%22%22\"\"1.301029996%2F0.84509804\"\"%22%22=%22%22\"\"1.53950185\" \n" ); document.write( "
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