document.write( "Question 91870This question is from textbook algebra and trigonometry
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document.write( ": One person can do a job in 8 hours. A second person can do it in 12 hours. If the first person works 2 hours less than the second, how many hours will it take them working together? PLEASE HELP \n" );
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Algebra.Com's Answer #66736 by mathispowerful(115)![]() ![]() ![]() You can put this solution on YOUR website! Assume it takes them T hours working together.\r \n" ); document.write( "\n" ); document.write( "then in one hour the first person can finish \n" ); document.write( "the second person can finish \n" ); document.write( "\n" ); document.write( "working together, the first person will spend T-2 hours, the second person will spend T hours\r \n" ); document.write( "\n" ); document.write( "the portion finished by first person is \n" ); document.write( "the portion finished by second person is \n" ); document.write( "\n" ); document.write( "together they finish the whole thing represented by 100% which is 1\r \n" ); document.write( "\n" ); document.write( "so we have \n" ); document.write( "\n" ); document.write( "multiply both sides by 24 we get\r \n" ); document.write( "\n" ); document.write( "3(T-2) + 2T = 24\r \n" ); document.write( "\n" ); document.write( "solve this equation we get T = 6 hrs. \r \n" ); document.write( "\n" ); document.write( "( I assume you know how to solve one variable equation)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |