document.write( "Question 91870This question is from textbook algebra and trigonometry
\n" ); document.write( ": One person can do a job in 8 hours. A second person can do it in 12 hours. If the first person works 2 hours less than the second, how many hours will it take them working together? PLEASE HELP \n" ); document.write( "
Algebra.Com's Answer #66733 by stanbon(75887)\"\" \"About 
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One person can do a job in 8 hours. A second person can do it in 12 hours. If the first person works 2 hours less than the second, how many hours will it take them working together?
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\n" ); document.write( "One person DATA;
\n" ); document.write( "Time = 8 hr/job ; Rate = 1/8 job/hr
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\n" ); document.write( "Second person DATA:
\n" ); document.write( "Time = 12 hr/job ; Rate = 1/12 job/hr
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\n" ); document.write( "Time on this job:
\n" ); document.write( "2nd person works x hours.
\n" ); document.write( "1st person works x-2 hours.
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\n" ); document.write( "EQUATION:
\n" ); document.write( "x(1/12) + (x-2)(1/8) = 1 job
\n" ); document.write( "Multiply thru by 24 to get:
\n" ); document.write( "2x + 3(x-2) = 24
\n" ); document.write( "2x + 3x-6 = 24
\n" ); document.write( "5x = 30
\n" ); document.write( "x = 6 hrs (how long 2nd person works)
\n" ); document.write( "x-2 = 4 hours (how long 1st person works)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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