document.write( "Question 91863This question is from textbook
\n" ); document.write( ": can you please help me solve this equation 12x^2 + 7 =10 ? \n" ); document.write( "
Algebra.Com's Answer #66731 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"12x%5E2+%2B+7x+=10\" I'm assuming it looks like this right?\r
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\n" ); document.write( "\n" ); document.write( "\"12x%5E2+%2B+7x+-10=0\" Subtract 10 from both sides\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"12%2Ax%5E2%2B7%2Ax-10=0\" ( notice \"a=12\", \"b=7\", and \"c=-10\")\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-7+%2B-+sqrt%28+%287%29%5E2-4%2A12%2A-10+%29%29%2F%282%2A12%29\" Plug in a=12, b=7, and c=-10\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-7+%2B-+sqrt%28+49-4%2A12%2A-10+%29%29%2F%282%2A12%29\" Square 7 to get 49 \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-7+%2B-+sqrt%28+49%2B480+%29%29%2F%282%2A12%29\" Multiply \"-4%2A-10%2A12\" to get \"480\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-7+%2B-+sqrt%28+529+%29%29%2F%282%2A12%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-7+%2B-+23%29%2F%282%2A12%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-7+%2B-+23%29%2F24\" Multiply 2 and 12 to get 24\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-7+%2B+23%29%2F24\" or \"x+=+%28-7+-+23%29%2F24\"\r
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\n" ); document.write( "\n" ); document.write( "Lets look at the first part:\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-7+%2B+23%29%2F24\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=16%2F24\" Add the terms in the numerator\r
\n" ); document.write( "\n" ); document.write( "\"x=2%2F3\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So one answer is\r
\n" ); document.write( "\n" ); document.write( "\"x=2%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "Now lets look at the second part:\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-7+-+23%29%2F24\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=-30%2F24\" Subtract the terms in the numerator\r
\n" ); document.write( "\n" ); document.write( "\"x=-5%2F4\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So another answer is\r
\n" ); document.write( "\n" ); document.write( "\"x=-5%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "So our solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"x=2%2F3\" or \"x=-5%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "Notice when we graph \"12%2Ax%5E2%2B7%2Ax-10\", we get:\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-15%2C+12%2C+-15%2C+12%2C12%2Ax%5E2%2B7%2Ax%2B-10%29+\"\r
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\n" ); document.write( "\n" ); document.write( "and we can see that the roots are \"x=2%2F3\" and \"x=-5%2F4\". This verifies our answer
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