document.write( "Question 1051836: Find two numbers where three times the smaller number exceeds the larger by 5 and the sum of the numbers is 11. \n" ); document.write( "
Algebra.Com's Answer #667302 by addingup(3677)\"\" \"About 
You can put this solution on YOUR website!
x+y = 11 and if we subtract y on both sides:
\n" ); document.write( "x = 11-y we'll use this value for x below.
\n" ); document.write( "Then the problem says:
\n" ); document.write( "3x = y+5 in this equation, substitute for x:
\n" ); document.write( "3(11-y) = y+5
\n" ); document.write( "33-3y = y+5 subtract 5 and add 3y on both sides:
\n" ); document.write( "28 = 4y
\n" ); document.write( "or
\n" ); document.write( "4y = 28 divide both sides by 4
\n" ); document.write( "y = 7
\n" ); document.write( "and we said that x = 11-y = 11-7 = 4
\n" ); document.write( "Your answer:
\n" ); document.write( "x = 4
\n" ); document.write( "y = 7
\n" ); document.write( "-------------------
\n" ); document.write( "Check:
\n" ); document.write( "3*the smaller exceeds the larger by 5:
\n" ); document.write( "3*4 = 12 and 12-7 = 5 Correct
\n" ); document.write( ":
\n" ); document.write( "John \n" ); document.write( "
\n" );