document.write( "Question 1051789: john invested 50,000, part of it at 6% and the other part at 8%. The annual interest on the 6% investment was 480 more than that from the 8% investment. How much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #667272 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
x=amount at 6%
\n" ); document.write( "50000-x=amount at 8%
\n" ); document.write( "0.06x-480=0.08(50000-x)=4000-0.08x
\n" ); document.write( "move the -0,08x to the left and the 480 to the right
\n" ); document.write( "0.14x=4480
\n" ); document.write( "x=$32,000@6%=$1920
\n" ); document.write( "50,000-x=$18,000@8%=$1440, and that is $480 less than $1920.
\n" ); document.write( "
\n" ); document.write( "
\n" );