document.write( "Question 1051789: john invested 50,000, part of it at 6% and the other part at 8%. The annual interest on the 6% investment was 480 more than that from the 8% investment. How much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #667272 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x=amount at 6% \n" ); document.write( "50000-x=amount at 8% \n" ); document.write( "0.06x-480=0.08(50000-x)=4000-0.08x \n" ); document.write( "move the -0,08x to the left and the 480 to the right \n" ); document.write( "0.14x=4480 \n" ); document.write( "x=$32,000@6%=$1920 \n" ); document.write( "50,000-x=$18,000@8%=$1440, and that is $480 less than $1920. \n" ); document.write( " \n" ); document.write( " |