document.write( "Question 1051773: a. x^3+9
\n" ); document.write( "b. When using long division, what binomial would you divide by to determine if -1 is a zero for your polynomial?
\n" ); document.write( "c. Do the long division you just described in part b. Show all your work.
\n" ); document.write( "d. Is -1 a zero? Explain how you can tell from the long division work.\r
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Algebra.Com's Answer #667236 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
If -1 is a 0, then x+1 is the binomial, because x=1=0, and x=-1
\n" ); document.write( "=======x^2
\n" ); document.write( "x-1/x^3+0x^2+0x+9
\n" ); document.write( "====x^3-x^2
\n" ); document.write( "change signs and subtract
\n" ); document.write( "======-x
\n" ); document.write( "x-1/-x^2+0x+9
\n" ); document.write( "====-x^2+x
\n" ); document.write( "change signs and subtract
\n" ); document.write( "=====-x +9
\n" ); document.write( "x-1 does not divide evenly into -x+9, so -1 is not a 0.
\n" ); document.write( "f(-1)=-1+9=8, which is not 0.
\n" ); document.write( "graph confirms that:\"graph%28300%2C300%2C-10%2C10%2C-10%2C10%2Cx%5E3%2B9%29\"
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