document.write( "Question 1051766: Daniel can encode a paper in 5 hours and together he and Dennis can encode it in 2 hours, how long would it take Dennis to encode the same paper alone? \n" ); document.write( "

Algebra.Com's Answer #667220 by jorel555(1290) $\"\"$ $\"About$

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If Daniel can encode a paper in 5 hours, then he encodes 1/5th paper per hour. Let n be the time it takes Dennis to encode a paper. Then:
\n" ); document.write( "1/5 + 1/n=1/2
\n" ); document.write( "2n+10=5n
\n" ); document.write( "10=3n
\n" ); document.write( "n=10/3
\n" ); document.write( "It takes Dennis 10/3 hours to encode the paper alone. ☺☺☺☺ \n" ); document.write( "

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