document.write( "Question 1051752: Juanita invested $13,000 for one year, part at 9 percent annual interest and the rest at 7 percent annual interest. How much must she invest at 9 percent to get $1,000 in interest in a year? \n" ); document.write( "
Algebra.Com's Answer #667219 by jorel555(1290)\"\" \"About 
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Let n be the amount Juanita invested at 9%. Then:
\n" ); document.write( ".09n+.07(13000-n)=1000
\n" ); document.write( ".02n=90
\n" ); document.write( "n=4500
\n" ); document.write( "Juanita needs to invest $4500 at 9%, and the rest at 7% to earn $1000 interest for the year. ☺☺☺☺
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