document.write( "Question 1051752: Juanita invested $13,000 for one year, part at 9 percent annual interest and the rest at 7 percent annual interest. How much must she invest at 9 percent to get $1,000 in interest in a year? \n" ); document.write( "
Algebra.Com's Answer #667219 by jorel555(1290)![]() ![]() ![]() You can put this solution on YOUR website! Let n be the amount Juanita invested at 9%. Then: \n" ); document.write( ".09n+.07(13000-n)=1000 \n" ); document.write( ".02n=90 \n" ); document.write( "n=4500 \n" ); document.write( "Juanita needs to invest $4500 at 9%, and the rest at 7% to earn $1000 interest for the year. ☺☺☺☺ \n" ); document.write( " |