document.write( "Question 1051682: Joe has 2 more quarters than nickels and 5 timed as many nickels as dimes. Altogether he has $6.90. How many dimes doed Joe have? \n" ); document.write( "

Algebra.Com's Answer #667179 by ikleyn(52848) $\"\"$ $\"About$

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\n" ); document.write( "Joe has 2 more quarters than nickels and 5 times as many nickels as dimes. Altogether he has $6.90. How many dimes does Joe have?
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document.write( "Let \"d\" be the number of dimes.\r\n" );
document.write( "Then the number of nickels is 5d,\r\n" );
document.write( "and the number of quarters is (5d+2).\r\n" );
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document.write( "The dimes contribute 10d cents to the total.\r\n" );
document.write( "The nickels contribute 5*(5d) = 25d cents to the total.\r\n" );
document.write( "The quarters contribute 25*(5d+2) = 125d + 50 cents to the total.\r\n" );
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document.write( "Therefore, the \"value\" equation is\r\n" );
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document.write( "10d + 25d + 125d + 50 = 690   (cents).\r\n" );
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document.write( "Simplify and solve for d:\r\n" );
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document.write( "160d + 50 = 690,\r\n" );
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document.write( "160d = 690-40,\r\n" );
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document.write( "160d = 640  --->  d =  = 4.\r\n" );
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document.write( "Answer. The number of dimes is 4.  The number of nickels is 4*5 = 20.  The number of quarters is 5*4+2 = 22.\r\n" );
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document.write( "Check.  5*20 + 10*4 + 22*25 = 690.  Correct !\r\n" );
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\n" ); document.write( "\n" ); document.write( "    - Coin problems\r
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\n" ); document.write( "\n" ); document.write( "    - Kevin and Randy Muise have a jar containing coins\r
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