document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1051664>Question 1051664</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 50 inches.if its length is two times its width, find the dimension of the rectangle  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #667126 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=667126\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L = 2W<BR>\n" );
document.write( "2L+2W = 50 substitute for L<BR>\n" );
document.write( "2(2W)+2W = 50<BR>\n" );
document.write( "4W+2W = 50<BR>\n" );
document.write( "6W = 50<BR>\n" );
document.write( "W = 8.33<BR>\n" );
document.write( "Note: Are you sure the perimeter is not 54? That would make the width a round 9. But you may have it right, different math teachers think differently. </SPAN>\n" );
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