document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1051628>Question 1051628</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm am really not sure where to begin to solve this problem. I know that I should set one side of the equation to 6 1/2. The question is:\r<BR>\n" );
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document.write( "In her Job at the post office, Janie works a 6 1/2 hour day. She sorts mail, sells stamps, and does supervisory work. On one day, she sold stamps twice as long as she sorted mail, and sold stamps 1 hour longer that the time she spent doing supervisory work. How many hours did she spend at each task? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #667091 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=667091\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sell stamps=x hours<BR>\n" );
document.write( "sorted mail is 1/2*x, half as long<BR>\n" );
document.write( "supervisory work is x-1<BR>\n" );
document.write( "They add to 6.5<BR>\n" );
document.write( "x+0.5x+x-1=6.5<BR>\n" );
document.write( "2.5x-1=6.5<BR>\n" );
document.write( "2.5x=7.5<BR>\n" );
document.write( "x=3 hours (sell stamps)<BR>\n" );
document.write( "sorted mail is 1.5 hours, or half of 3.<BR>\n" );
document.write( "supervisory work was 2 hours, or x-1<BR>\n" );
document.write( "They add to 6.5 hours </SPAN>\n" );
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