document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1051593>Question 1051593</A>: <I><SPAN STYLE=\"word-break: break-all;\"> y=(-1/2) x^2-3x+11<BR>\n" );
document.write( "find the max or min value ofy and the value of x when it occurs. thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #667067 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=667067\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=(-1/2) x^2-3x+11<BR>\n" );
document.write( "find the max or min value of y and the value of x when it occurs. thanks. <BR>\n" );
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document.write( "Since the coefficient of x^2 is negative, y has a maximum value.<BR>\n" );
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document.write( "Note:: Max occurs when x = -b/(2a) = 3/(2(-1/2)) = 3/-1 = -3<BR>\n" );
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document.write( "The max value is f(-3) = (-1/2)(9)-3(-3)+11 = -4.5 + 20 = 15.5<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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