document.write( "Question 1051583: Can someone help me with this problem:\r
\n" ); document.write( "\n" ); document.write( "In a certain production process, 25% of the items produced are found defective. It therefore requires through inspection of all the items produced before packing them for sale.\r
\n" ); document.write( "\n" ); document.write( "a) Develop a probability density function for the number of non-defective items in a day's production of n items.\r
\n" ); document.write( "\n" ); document.write( "b) Using your answer to a), determine the probability of getting at least 50 good items if 100 items are produced.
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Algebra.Com's Answer #667057 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
a)
\n" ); document.write( "p(def) = .25, p(not def) = .75
\n" ); document.write( " probability density function for the number of non-defective items in a day's production of n items.
\n" ); document.write( "Let x represent the number of non-defective itemsin a day's production of n items
\n" ); document.write( "\"P+%28x%29=+highlight_green%28nCx%29%28.75%5Ex%29%28.25%29%5E%28n-x%29+\"
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\n" ); document.write( "b)
\n" ); document.write( "p = .75, n = 100
\n" ); document.write( "P (x>= 50) Commulative Probability\r
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\n" ); document.write( "P (x>= 50) = 1 - binomcdf(100,.75,49) = 1 - .000002 = .999998
\n" ); document.write( "P (x>= 50) basically a sure thing. \r
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